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YCC module: never fail, even if bad URL is given

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nemunaire 2014-05-01 23:36:21 +02:00
parent d56f873fd4
commit 471e40aed1
1 changed files with 12 additions and 9 deletions
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21
modules/ycc.py
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@ -58,15 +58,18 @@ def cmd_ycc(msg):
def parselisten(msg):
global LAST_URLS
urls = re.findall("([a-zA-Z0-9+.-]+:(//)?[^ ]+)", msg.content)
for (url, osef) in urls:
o = urlparse(url)
if o.scheme != "":
if o.netloc == "ycc.fr" or (o.netloc == "" and len(o.path) < 10):
continue
if msg.channel not in LAST_URLS:
LAST_URLS[msg.channel] = list()
LAST_URLS[msg.channel].append(o.geturl())
try:
urls = re.findall("([a-zA-Z0-9+.-]+:(?://)?[^ ]+)", msg.content)
for url in urls:
o = urlparse(url)
if o.scheme != "":
if o.netloc == "ycc.fr" or (o.netloc == "" and len(o.path) < 10):
continue
if msg.channel not in LAST_URLS:
LAST_URLS[msg.channel] = list()
LAST_URLS[msg.channel].append(o.geturl())
except:
pass
return False
def parseresponse(res):